Sum of n terms of an a.p is sn=3n^2 + 6n.find nth term ?
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Given Sn = 3n2 + 6n
S1 = 3×1 + 6×1 = 9
S2 = 3×4 + 6×2 = 12 + 12 = 24 .
Therfore First term a1 = 9 & Second term a2 = 24 - 9 = 15 and d = 15 - 9 = 6.
Now nth term an = 7 + ( n - 1) 6
S1 = 3×1 + 6×1 = 9
S2 = 3×4 + 6×2 = 12 + 12 = 24 .
Therfore First term a1 = 9 & Second term a2 = 24 - 9 = 15 and d = 15 - 9 = 6.
Now nth term an = 7 + ( n - 1) 6
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