Sum of n terms of an ap is n/2[a+(n-1) ]
pk6705125:
sum of nth term of an Ap is n/2{a+(n-1)}
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Answer:
Sum of n terms of an AP is n/2[2a+(n-1)d ]
where, n --> no. of terms
a --> first term
d --> common difference
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Answered by
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Step-by-step explanation:
sn= sum of nth term
a= first term
d=common difference
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