sum of n terms of an arithmetic progression 1+3+5+7+9
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1
Answer:
n^2
Step-by-step explanation:
1+3+5+7+9..
a=1 (first term)
d=3-1=2(common difference)
sum of n terms sn=n/2[2a+(n-1)d]
sn=n/2[2×1+(n-1)2]
=n/2[2+2n-2]
=n/2[2n]
=n[n]
=n^2
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2
Answer:
Correct answer of this question is n^2
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