Math, asked by nehasatish2006, 2 months ago

sum of n terms of an arithmetic progression 1+3+5+7+9​

Answers

Answered by richitha77
1

Answer:

n^2

Step-by-step explanation:

1+3+5+7+9..

a=1 (first term)

d=3-1=2(common difference)

sum of n terms sn=n/2[2a+(n-1)d]

sn=n/2[2×1+(n-1)2]

=n/2[2+2n-2]

=n/2[2n]

=n[n]

=n^2

Answered by Srishtikokra
2

Answer:

Correct answer of this question is n^2

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