SUM OF N TERMS OF H.P.
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◆ Since 1/AP = HP
So, the formula is:
∆◆ 1/Sn = 2/n [1/2a + 1/(n-1)d]
&
∆◆ 1/Sn = 2/n ( 1/a+1/l )
HOPE IT HELPS
◆ Since 1/AP = HP
So, the formula is:
∆◆ 1/Sn = 2/n [1/2a + 1/(n-1)d]
&
∆◆ 1/Sn = 2/n ( 1/a+1/l )
HOPE IT HELPS
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