Math, asked by taruntarun2936, 6 months ago

Sum of n terms of the series √3 + √27 +√75 + √147 + ... is
(a) n(n+1)/2
(b) 2n(n+1)
(c) √3n²
(d) 1

Answers

Answered by gopalpvr
1

Step-by-step explanation:

√3 + √27 +√75 + √147 + ..

=√3 (1+ √9 +√25 + √49 + ... )

=√3 (1+3+5+7...)

=√3n²

since we know that1+3+5+7....=n²

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