Sum of n terms of the series √3 + √27 +√75 + √147 + ... is
(a) n(n+1)/2
(b) 2n(n+1)
(c) √3n²
(d) 1
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Step-by-step explanation:
√3 + √27 +√75 + √147 + ..
=√3 (1+ √9 +√25 + √49 + ... )
=√3 (1+3+5+7...)
=√3n²
since we know that1+3+5+7....=n²
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