Math, asked by harshit30june, 10 months ago

Sum of number of pentagonal and
rectangular faces is x in truncated
pentagonal bipyramidal geometry, then
find the value of 2x.​

Answers

Answered by topwriters
0

2x = 14

Step-by-step explanation:

The pentagonal bipyramid is third of the infinite set of face-transitive bipyramids.

  • Each bipyramid is the dual of a uniform prism.
  • Although it is face-transitive, it is not a Platonic solid because some vertices have four faces meeting and others have five faces.
  • The pentagonal bipyramid, dt{2,5}, can be truncated, trdt{2,5}.
  • The dual of the Johnson solid pentagonal bipyramid is the pentagonal prism, with 7 faces: 5 rectangular faces and 2 pentagons.

So x = 2 + 5 = 7

Therefore 2x = 2 * 7 = 14

Answered by SerenaBochenek
0

The value of 2x will be "14".

Step-by-step explanation:

  • However it's facial expression-transitive, that's not a Platonic hard material, because certain vertexes having 4 faces seemed to have 5 faces.  
  • The pentagonal bi-pyramide,

⇒  dt{2,5}

  • could be abbreviated,

⇒  trdt{2,5}.  

Now,

⇒  x=2+5

       =7

So,

⇒  2x=2\times 7

         =14

Learn more:

https://brainly.in/question/17841422

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