Question

Sum of numbers and its reciprocal is 281/80 Find numbers

Answer 1

Answer:

Hello There,

This is your answer.

Step by step explanation:

Let the number be x.

So, its reciprocal is 1/x.

X + 1/X = 281/80

(X^2+1)/X = 281/80

( X^2 + 1 ) = 281x / 80

80(X^2+1)=281x

80X^2+80=281x

80X^2 - 281x+80=0

80X^2-256x-25x+80=0 (Splitting the middle term method)

16x(5x-16)-5(5x-16)=0

(16x-5)(5x-16)=0

(16x-5) = 0 or (5x-16) = 0

x = 5/16 or x =16/5.

HOPE IT HELPS YOU!!!