sum of numerator and denominator of a fraction is 1 less than thrice the numenator. if numinator and denominator are increased by 2 ratio of numerator to denominator would be 3:5 find the fraction
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7/13
Step-by-step explanation:
Let numerator = x , Denomenater = y x+y = 3x - 1 2x = 1 + y
x = (1 + y)/2
SECOND EQUATION
(x + 2)/(y + 2) = 3/5
5x + 10 = 3y + 6
5x - 3y = 6 - 10
5x - 3y = - 4
5 [( 1 + y ) / 2] - 3y = - 4
( 5 + 5y - 6y ) / 2 = - 4
5 - y = - 8
y = 13
x = ( 1 + 13 ) / 2
x = 7
Required Fraction = 7 / 13
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