Question

sum of
of the areas
squares is 400 cm2 and the difference of their perimeter is 16cm .find the sides of the two squares​

Answer 1

Let side of 1st square=x cm.

∴ Area of 1st square=x²cm²

GIVEN, Sum of areas =400cm²

∴ Area of 2nd square=(400-x²)cm²

AND side of 2nd square=√[(20-x)² i.e.20-x .......(1)

Difference of perimeters=16cm.

THEN-

4x-4(20-x)=16 (ASSUMING THAT 1ST SQUARE HAS LARGER SIDE)

X=12

HENCE - SIDE OF 1ST SQUARE = 12CM ;

SIDE OF 2ND SQUARE=20-12=8CM. [FROM (1)]

WHICH IS NOT THE REQUIRED ANSWER AS SUM OF AREAS OF SQUARES OF FOUNDED SIDES IS NOT 400CM²