Question

sum of perimeter of two rectangles is 216 cm and length of both rectangle are in ratio 3: 2. If breadth of both rectangle are equal to the side of square whose area 196 cm2 Then find sum of area of ​​both rectangle?​

Answer 1

Answer:

1120 cm²

Step-by-step explanation:

$P_{}$ = $P_{1}$ + $P_{2}$

6x + 28 + 4x + 28 = 216

10x = 216 - 56

10x = 160 ⇒ x = 16

Thus, length of first rectangle is 3 × 16 = 48 cm and length of second rectangle is 2 × 16 = 32 cm and breadth of each rectangle is 14 cm.

$A_{}$ = $A_{1}$ + $A_{2}$

$A_{1}$ = 48 × 14 = 672 cm² and $A_{2}$ = 32 × 14 = 448 cm²

A = 1120 cm²