Question

sum of present age of ram sham is 39 years three year ago ram was twice the age of sham find their ages​

Answer 1

Let the present age of ram be x.

and present age of shyam be y.

Now,

Given first condition,

$\bf \to \: x + y = 39 \: yrs. \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \bf \: \: \: x = 39 - y....eq.1$

Given second condition,

Three years ago,

Ram age = x -3

Shyam age = y-3

$\to \bf x-3 =2 (y -3)\\ \to \bf \: 39-y-3 = 2y-6....(from \: eq.1) \\ \bf \to \: 36 = 3y -6\\ \bf \to \: y = \frac{42}{3}$

$\small \to {\boxed {\tt \blue {y = 14 }}}$

Putting y = 14,

$\bf \to \: x + y = 39 \\ \bf \to x = 39 - 14$

$\small \to {\boxed {\tt \blue {x= 25 }}}$

So,

$\sf x = age \: of \: ram = 14} \\ \sf \: and \: \: \underline{y = age \: of \: shyam \: = 25$

$\bf \therefore Ages- \\ \underline{\bf \: \: \: \: \bullet x = age \: of \: ram = 14} \\ \bf \: \: \: \: \underline{\bullet x = age \: of \: shyam = 25}$

Answer 2

Given ,

• The sum of present age of ram and sham is 39

• Three years ago , the ram was twice the age of sham

Let , the present age of ram and sham be x and y

According to the question ,

x + y = 39 --- (i)

and

x - 3 = 2(y - 3)

x = 2y - 3 --- (ii)

From eq (i) and eq (ii) , we get

2y - 3 + y = 39

3y - 3 = 39

3y = 42

y = 14

Put the value of y = 14 in eq (i) , we get

x + 14 = 39

x = 25

$\therefore \sf \underline{The \: present \: ages \: of \: ram \: and \: sham \: 25 \: years \: and \: 14 \: years \: }$