Question

Sum of Present ages of two friends are 23years. Five years ago product of their ages was 42. Find their ages 5 years hence.​

Answer 1

i just skipped one step.... that...
x= 11 or x= 12

hope it helps

$\textbf{plz mark brainlest }$

Answer 2

Answer:

16 years and 17 years

Step-by-step explanation:

Consider the present age of friend A is = $x$ year

Consider the present age of friend B is = $y$ year

As per the problem, Sum of their present age is =23 years

$\therefore(x+y)=23\\\\x=23-y....................\text{equation-1}$

Five years ago age of the friend A was =$(x-5)$ years

Five years ago age of the friend B was =$(y-5)$ years

As per the problem, Five years ago product of their age were =42 years

$\therefore(x-5)\times(y-5)=42\\\\\Rightarrow(23-y-5)(y-5)=42\\\\\Rightarrow(18-y)(y-5)=42\\\\\Rightarrow(18y-90-y^{2}+5y)=42\\\\\Rightarrow(23y-90-y^{2})=42\\\\\Rightarrow(42-23y+90+y^{2})=0\\\\\Rightarrow(y^{2}-23y+132)=0\\\\\Rightarrow(y^{2}-12y-11y+132)=0\\\\\Rightarrow y(y-12)-11(y-12)=0\\\\\Rightarrow (y-12)(y-11)=0$

As $(y-12)(y-11)=0$

therefore $y=11$ or $y=12$

If $y=11$ then $x=23-y=23-11=12$

If $y=12$ then $x=23-y=23-12=11$

therefore the present age of the two friends are 11 years and 12 years

therefore the age of the two friends after five years are $(11+5)=16$ years and $(12+5)=17$ years