Question

sum of real values of y satisfying the equation x²+x²y²+x²y⁴=525 and x+xy+xy²=35 is:
A 15
B 10
C 5/3
D 3/2​

Answer 1

Please mark as brainliest

x²·(1+y²+y^4)=525

x·(1+y+y²)=35 --> x²·(1+2y+3y²+2y³+y^4)=1225

2ª/1ª: (1+2y+3y²+2y³+y^4)/(1+y²+y^4)=7/3

--> 7·y^4+7y²+7= 3y^4+6y³+9y²+6y+3 -->

4·y^4-6y³-2·y²-6y+4=0 -->

2·y^4-3y³-·y²-3y+2=0 -->

(y²+y+1)·(2y²-5y+2)=0 -->

y=2 or y=1/2

*If y=2 --> x·(1+2+4)=35 --> x=5

*If y=1/2 --> 7/4·x=35 --> x= 20

Answer 2

I hope it's helpful

I think your options are incorrect.