sum of resiprocules of two consicative odd natural number is 12/35 find those number
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Answer:
required numbers are 5 and 7
Step-by-step explanation:
suppose two numbers are x,x+2
according to given conditions
1/x+1/x+2=12/35
on solving we get
6x^×-23x-35=0
on solving we get
x=5 or x= -7/6
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