Sum of roots of a quadratic equation is double their product. Find 'k' if the equation is 4kx + k + 3 = 0
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Hi ,
Compare x² - 4kx + ( k + 3 ) = 0 with
ax² + bx + c = 0 we get ,
a = 1 ,
b = - 4k ,
c = ( k + 3 ),
1 ) sum of the Roots = - b/a
= - ( - 4k )/1
= 4k
2 ) product of the roots = c/a
= ( k + 3 )/1
= k + 3
according to the problem given ,
4k = 2( k + 3 )
4k = 2k + 6
4k - 2k = 6
2k = 6
k = 6/2
k = 3
I hope this helps you.
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