Question

Sum of roots of a quadratic equation is double their product. Find k if equation is
x^2-4kx+k+3=0

Answer 1

This is the solution for your question

Answer 2

$[]\large{\underline{\sf{\red{To \: Find-}}}}$

Value of k.

$[]\large{\underline{\sf{\red{Solution-}}}}$

Here,

a = 1

b = -4k

c = k + 3

$[]:\implies\rm{α + β = 2α β } \: .... \: (1) \\ </p><p></p><p>:\implies\rm{α + β = - \frac{b}{a}} \\ </p><p> </p><p> </p><p>:\implies\rm{α + β = - \frac{b}{a}} \\ </p><p> </p><p>:\implies\rm{α + β = - \frac{ - 4k}{1} = 4k} \: ... \: (2) \\ </p><p></p><p>:\implies\rm{αβ = \frac{c}{a} = \frac{k + 3}{1} } \\ </p><p></p><p>:\implies\rm{α β = k + 3 }\: ... \: (3)</p><p>$

From (1), (2) and (3),

$</p><p>[tex][]:\implies\rm{4k = 2(k + 3)} \\ </p><p>:\implies\rm{4k - 2k = 6} \\ </p><p>:\implies\rm{2k = 6} \\ </p><p>\boxed{\rm\red{k = 3}} </p><p>$

[/tex]

Hence,

The Value of k is 3.