sum of roots of ax square+2cx+b is 0
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We have the equations ax^2 + 2cx + b = 0 and ax^2 + 2bx + c = 0 and its given that they have a common root. So assume that common roots is p.
Then we'll have
ap^2 + 2cp + b = 0
ap^2 + 2bp + c = 0
Subtracting these two equations, we'll get
2p(c - b) + (b - c) = 0
=> 2p(c - b) = (c - b)
Since c = b, (c - b) = 0, which means we can divide both the sides of the equation by (c - b). Doing so, we'll get,
=> 2p = 1
=> p = 1/2
Which means the common roots is 1/2. This means x = 1/2 will satisfy both the equations.
Now putting x = 1 in ax^2 + 2cx + b = 0, we'll get
a(1/2)^2 + 2c(1/2) + b = 0
=> a/4 + c + b = 0
=> (a + 4c + 4b)/4 = 0
=> a + 4b + 4c = 0
So, a + 4b + 4c is 0
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Answer:
2p = 1
P = 1/2
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