Question

Sum of rs 2387 is divided into three parts in such a way that one fifth of the first part,one half of the second part and fourth one the third part are equal. find the sum of five times the first part,three times the second part and four times the third part (in rupees).

Answer 1

Let sum of Rs.2387 is divided into three parts X, Y and Z .
according to question,
X/5 = Y/2 = Z/4 = k (let)
X = 5K
Y = 2K
Z = 4K
now, X + Y + Z = 2387
5k + 2k + 4k = 2387
11k = 2387
k = 217


so, 1st part , X = 5K = 5 × 217 = 1085
2nd part, Y = 2k = 2 × 217 = 434
3rd part , Z = 4k = 4 × 217 = 868

now, 5times of 1st part = 5X = 5 × 1085 = 5425
three times of 2nd part = 3Y = 3 × 434 = 1302
2nd times of 3rd part = 2Z = 2 × 868 = 1736

Answer 2

Answer:12199

Step-by-step explanation:

Abhi178 The Sage

Let sum of Rs.2387 is divided into three parts X, Y and Z .

according to question,

X/5 = Y/2 = Z/4 = k (let)

X = 5K

Y = 2K

Z = 4K

now, X + Y + Z = 2387

5k + 2k + 4k = 2387

11k = 2387

k = 217

so, 1st part , X = 5K = 5 × 217 = 1085

2nd part, Y = 2k = 2 × 217 = 434

3rd part , Z = 4k = 4 × 217 = 868

now, 5times of 1st part = 5X = 5 × 1085 = 5425

three times of 2nd part = 3Y = 3 × 434 = 1302

four times of 3rd part = 4Z = 4 × 868 = 3472