Question

sum of rupees 20000 is lent of CI for 3 years if the rate of interest for 3 successive 5% 6% and 8% find the amount received back at the end of 3 years​

Answer 1

Let the sum be Rs x.

We know that:

CI = A – P

= P(1+R100)n – P

= P[(1+R100)n−1]

164 = x[(1+5100)2−1]

164 = x[(1.05)2−1]

x = 1640.1025

x = 1600

Thus, the required sum is Rs 1600.

Answer 2

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REFER THE ATTACHMENTS