Question

sum of rupees 64000 produces and interest of rupees 4921 Ban deposited in a bank for 3 years find the rate of interest​

Answer 1

Given:

The sum of rupees 64000 produces an interest of rupees 4921 in a bank for 3 years

To find:

The rate of interest​

Solution:

To solve the given problem we will use the following formula of simple interest:

$\boxed{\bold{Simple\:Interest = \frac{P\times R\times T}{100} }}$

Here

P = Principal = Rs. 64000

R = Rate of interest  

T = Time period = 3 years

S.I. = 4921

Now, substituting the given values in the formula, we get

$4921 = \frac{64000\times R\times 3}{100} }}$

$\implies 4921 \times 100 = 64000\times R\times 3$

$\implies 492100 = 192000\times R$

$\implies R = \frac{492100}{192000}$

$\implies \bold{R = 2.56\%}$

Thus, the rate of interest is 2.56 %.

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Answer 2

Answer:

Answer:16,6250

Step-by-step explanation:

3 years = 3(20,000)+3(25000)+1(31250)

=166250

Step-by-step explanation: