sum of sequence 5+10+15+ 20+25+.......+100
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Ans : 2100
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an=100
a=5
d=10-5(a2-a1)=5
by using an=a+(n-1)d
100=5+(n-1)5
100-5=5n-5
95=5n-5
5n=95+5
5n=100
n=100/5
n=20
now by using sn=n/2(a+an)
20/2(5+100)
10(105)
=1050
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