sum of series in c++ 2, 4, 6.......n
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ANSWER
Let T
n
is the nth term
Then sum upto n term is
S=1+3+7+15+31+......+T
n
...(1)
Again S=1+3+7+15+......+T
n−1
+T
n
...(2)
Subtracting (2) -(1) we get
0=1+[2+4+8+16+.....(T
n
−T
n1
)]−T
n
T
n
=1+2+2
2
+2
3
+2
4
+ upto n terms
Therefore
S=∑T
n
=∑2
n−1
=(2+2
2
+2
3
+......+2
n
)n=2(
2−1
2
n
−1
)n=2
n+1
n−2n
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