Question

Sum of sges of father and son is 58 years and four years hence the fathers ages will be two times of son age then find the ages of son and father respectivrly

Answer 1

Answer:-

Let the son's age be "x" and father's age be "y".

Given:

sum of their ages = 58 years

→ x + y = 58

→ y = 58 - x -- equation (1)

And,

After 4 years father's age is twice the age of son.

→ Father's age after 4 years = y + 5

→ son's age after 4 years = x + 5

According to the above condition,

→ y + 4 = 2 (x + 4)

→ y + 4 = 2x + 8

Substitute the value of "y" from equation (1)

→ 58 - x + 4 = 2x

→ 58 + 4 - 8 = 2x + x

→ 3x = 54

→ x = 54/3

→ x = 18

Putting the value of "x" in equation (1) we get,

→ y = 58 - x

→ y = 58 - 18

→ y = 40

Hence,

• Present age of son (x) = 18 years.

• Present age of father (y) = 40 years.

Answer 2

Answer:

Age of father = 40 years and son = 18 years

Step-by-step explanation:

Assume that the age of father be x years and son be y years.

Sum of sges of father and son is 58 years.

→ x + y = 58

→ x = 58 - y ................(1)

Four years hence the fathers ages will be two times of son age.

After 4 years:

• Age of father = (x + 4) years
• Age of son = (y + 4) years

As per given condition,

→ x + 4 = 2(y + 4)

→ x + 4 = 2y + 8

→ x = 2y + 4

Substitute the value of x in above equation,

→ 58 - y = 2y + 4

→ 54 = 3y

→ 18 = y

Substitute value of y in x

→ x = 58 - 18

→ x = 40

Hence, the age of father is 40 years and son is 18 years.