Question

sum of sixth term in an ap is 345 the difference between the first and the last term is 55 find the term

Answer 1

Let the first term be a

and common difference be d

6th term = a +(6-1)d = a -5d

A/q

(a+5d) -a = 55

⇒5d = 55

⇒d = 11

also, 

S6 = (6/2)[2a+(6-1)×11] = 345

⇒2a +55 = 115

⇒2a = 60

⇒a = 30

so AP = 30,41,52,63,74,85,96.....so on

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