Question

sum of sixth term in an ap is345 the difference between the the first and the last term is 55 find the term

Answer 1

An = a + (n-1)d

An can be written as last term(l)

New  formula

l = a + (n-1)d

l - a = (n - 1)d

55 = (n-1) * d......................................eq1

Now,

S6 = n/2 (2a + (n-1)d)

345 = 6/2 (2a + 55)                                             ( from eq1 (n-1)d = 55 )

345/3 - 55 = 2a

a = 30

If you understood the answert mark it as brainliest :)