Question

sum of square of two num is 233 & one of the num is 3 less than twice the other num the num areare

Answer 1

Answer:

8 and 13

Step-by-step explanation:

let one number be x

the other number is 2x - 3

${x}^{2} + {(2x - 3)}^{2} = 233 \\ {x}^{2} + 4 {x}^{2} - 12x + 9 = 233 \\ {5x}^{2} - 12x - 224 = 0 \\ \\ 5 {x}^{2} - 40x + 28x - 224 = 0 \\ 5x(x - 8) + 28(x - 8) = 0 \\ (5x + 28)(x - 8) = 0 \\ 5x + 28 = 0 \: \: \: \: \: \: \: \: x - 8 = 0 \\ x = \frac{ - 28}{5} \: \: \: \: \: \: \: \: x = 8$

the first number is 8

second number is 2x - 3 = 2(8) - 3 = 16 - 3 = 13