Math, asked by mayankisdumb, 19 days ago

sum of squares of all integral values of a for which the equation (3 sin x - 4cos x)² - (a²+a+5)[3 sin x - 4 cos x]+a³+3a²+2a+6=0 has a real solution is​

Answers

Answered by giveawayoctopusg
0

Answer:

a = ax2 b =bx 3 okokkkkkkk

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