Question

Sum of squares of the two consecutive natural number is 625

Answer 1

x
${x}^{2} + (x + 1)^{2} = 625 \\ {x }^{2} + {x}^{2} + 1 + 2x = 625 \\ 2 {x}^{2} + 2x - 624 = 0 \\ {x }^{2} + x - 312 = 0$