Math, asked by babu139, 1 year ago

Sum of squares of the two consecutive natural number is 625

Answers

Answered by monikagupta1
2
x
{x}^{2}  +  (x + 1)^{2}  = 625 \\  {x }^{2}  +  {x}^{2}  + 1 + 2x = 625 \\ 2 {x}^{2}  + 2x - 624 = 0 \\  {x }^{2}  + x  - 312 = 0 \\
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