Question

Sum of squares of three consecutive odd numbers is 1091 the greatest number.

Answer 1

Answer:

21

Step-by-step explanation:

Let numbers are (x - 2), x, (x + 2), then

(x - 2)²+ x² + (x + 2)² = 1091

x² - 4x + 4 + x² + x² + 4x + 4 = 1091

3x² + 8 = 1091

3x² = 1083

x² = 361

$x_{12}$ = ± 19

If x = 19, then set of numbers is {17, 19, 21}

If x = - 19, then set of numbers is {- 21, - 19, -17}

The greatest number is 21