Question

Sum of squares of three consecutive odd numbers is 2531. which is the largest number

Answer 1

let the three consecutive odd numbers be n,n+2,n+4
n^2+(n+2)^2+(n+4)^2=2531
n^2+n^2+4+4n+n^2+16+8n=2531
3n^2+12n-2511=0
         divide equation with 3
n^2+4n-837=0
(n+31) (n-27)
 ignoring -31 as positive odd integers
Therefore the numbers are 27,29,31
The largest odd number is 31

Answer 2

hope this help.............