Question

Sum of squares of three positive numbers is 608
and they are in the ratio 2 : 3:5. Then, find the
numbers​

Answer 1

Answer:

8 , 12 , 16

Step-by-step explanation:

given that the ratio of three positive numbers = 2:3:5

let the ratio of numbers be x

then

numbers be 2x, 3x and 5x

Given that

Sum of squares of numbers = 608

ATQ,

(2x)² + (3x) ² + (5x) ² = 608

4x² + 9x² + 25x² = 608

38x² = 608

x² = 608/38

x² = 16

x = 4

so

the numbers are

2x = 2(4) = 8

3x = 3(4) = 12

5x = 5(4) = 20

Answer 2

Answer:

Step-by-step explanation:

We have ratio

2:3:5

. The sum of squaree =608

Let them x

It will be

2x,3x,5x

${(2x)}^{2} + {(3x)}^{2} + {(5x)}^{2} = 608$

${4x}^{2} + {9x}^{2} + {25x}^{2} = 608$

${38x}^{2} = 608$

${x}^{2} = \frac{608}{38}$

${x}^{2} = 16 \\ x = 4$

The numbers will be

2x=2(4)=8

3x=3(4)=12

5x=5(4)=20

The numbers will be 8,12,20