sum of squares of two consecutive even number by writing a suitable quadratic equation
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Let the number be x
Consecutive number = x+1
Let sum of squares = c
(x)^2 + (x+1)^2 = c
x^2 + x^2 +1+ 2x-c =0 {(a+b)^2 = a^2 + b^2 + 2ab}
2x^2 + 2x + (1-c) =0 is the required quadratic equation.
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