Question

Sum of squares of two consecutive even numbers​

Answer 1

x and x+1 are consecutive integers

now,

(x)²+(x+1)²=265

x²+x²+2x+1=265

2x²+2x=264

x²+x=132

x²+x-132=0

x²-11x+12x-132=0

(x+12)(x-11)=0

Therefore -12 or 11

x=11

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