Question

sum of squares of two consecutive natural even number is 244 find the numbers i.e x PLZ ANS THIS QUESTION ITS 10STD MATHS​

Answer 1

Answer:

10 and 12

Step-by-step explanation:

${x}^{2} + {(x + 2)}^{2} = 244 \\ {x}^{2} + {x}^{2} + 4x + 4 = 244 \\ 2 {x}^{2} + 4x - 240 = 0 \\ {x}^{2} + 2x - 120 = 0 \\ {x}^{2} + 12x - 10x - 120 = 0 \\ x(x + 12) - 10(x + 12) = 0 \\ (x - 10)(x + 12) = 0 \\ x = 10 \: \: \: \: x = - 12 \\ x = 10 \\ the \: numbers \: are \: x = 10 \\ x + 2 = 12$