Question

Sum of squares of two consecutive natural number is 244

Answer 1

let first natural even number be x

next consecutive number is x+2

by given condition ,

x^2 + (x+2)^2 = 244

x^2 + x^2+ 4x + 4 = 244

2x^2 + 4x + 4 =244

2x^2 + 2x + 4 - 244 = 0

2x^2 + 2x - 240 = 0

x^2 + x - 120 = 0

x^2 + 12x 10 x - 120 = 0

x ( x + 12 ) - 10 ( x + 12 ) = 0

( x + 12 ) ( x - 10 ) = 0

( x + 12 ) = 0 or ( x - 10 ) = 0

x = - 12 or x = 10

x = - 12 not possible

so ,

x = 10

numbers are 10 and 12

Answer 2

Step-by-step explanation:

I hope it will help you....