Question

sum of squares of two numbers is 145. if squares root of one number is 3, find the other number

Answer 1

Let the no be x and y

Then √x=3

x=9

9^2+y^2=145

y^2=145-81=64

y=8

Numbers are 9 and 8

Answer 2

Answer:

$\red { Required \: other \: number} = \green {8}$

Step-by-step explanation:

$Let \: First \: number = \blue x$

$Second \: number = \pink y$

$\sqrt{x} = 3 \: (given)$

/* On Squaring both sides of the equation,we get

$\implies (\sqrt{x})^{2} = 3^{2}$

$\implies x = 9$

/* According to the problem given ,

$\blue {x^{2}} +\pink {y^{2}} = 145 \:(given)$

$\implies 9^{2} + \pink {y^{2}} = 145$

$\implies 81 + \pink {y^{2}} = 145$

$\implies \pink {y^{2}} = 145 - 81$

$\implies \pink {y^{2}} = 145\\= 64$

$\implies y = \sqrt{64}$

$\implies \green {y} = \green { 8^{2}}= \green 8$

Therefore.,

$\red { Required \: other \: number} = \green {8}$

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