Question

sum of squares of two numbers is 145. If the square root of one number is 1 more than the other , find the square of the smaller number​

Answer 1

Step-by-step explanation:

माना बड़ी संख्या = x

& छोटी संख्या = y

x² + y² = 145 --------(1)

प्रश्नानुसार - x = y + 1 -----(2)

समी.(1) व (2) से

(y+1)² + y² = 145

y² + 2y + 1 + y² = 145

2y² + 2y - 144 = 0

y² + y - 72 = 0

y² + 9y - 8y - 72 = 0

y(y + 9) -8(y+9) = 0

(y - 8) (y + 9) = 0

y = 8✓ , y = -9

समी.(2) से

x = 8 + 1 = 9

बड़ी संख्या (x) = 9

छोटी संख्या(y) = 8

छोटी संख्या का वर्ग = y² = 64