Question

sum of squares of two numbers is 45 one number is twice the other number find the numbers​

Answer 1

Step-by-step explanation:

Let the first number be x then the other number is 2x.

Now, A/Q, x² + (2x)² = 45

= 3x² = 45

= x² = 15

= x = √15

SO THE FIRST NUMBER IS√15 AND THE OTHER NUMBER IS 2√15

Answer 2

Answer:

7.5

Step-by-step explanation:

x^2 + (x^2)^2 = 45

x^2 + x^(2+2) = 45

x^2 + x^4 = 45

x^(2+4) = 45

x^6 = 45

x = 45/6

x = 7.5

Hope this answer helped you!