sum of the 1/6 of a number and 3/8 the same number is 55 find the number
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Answered by
1
Answer:
Let the three numbers in G.P. be a,ar and ar
2
From the given condition
a+ar+ar
2
=56
⇒a(1+r+r
2
)=56...(1)
Also given a−1,ar−7,ar
2
−21 forms an A.P.
∴(ar−7)−(a−1)=(ar
2
−21)−(ar−7)
⇒ar−a−6=ar
2
−ar−14
⇒ar
2
−2ar+a=8
⇒a(r
2
+1−2r)=8
⇒a(r−1)
2
=8...(2)
Using (1) and (2)
⇒7(r
2
−2r+1)=1+r+r
2
⇒7r
2
−14r+7−1−r−r
2
=0
⇒6r
2
−15r+6=0
⇒6r
2
−12r−3r+6=0
⇒6r(r−2)−3(r−2)=0
⇒(6r−3)(r−2)=0⇒r=2,
2
1
When r=2, a=8
And three numbers in GP are 8,16 32.
When r=
2
1
, three numbers in G.P. are 32,16 and 8.
Thus in either case, the three required numbers are 8,16 and 32.
Answered by
5
Answer:
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