sum of the 2 digit no is 9 . If 63 is subracted from the no, its digits are reversed.find the no
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Let us assume, x and y are the two digits of a two digit number
Therfore, the two-digit number = 10x + y and reversed number = 10y + x
Given:
x + y = 9 ----------1
Also given:
10x + y - 63 = 10y + x
9x - 9y = 63
x - y = 7 ------------2
Adding equation 1 and equation 2
2x = 16
x = 8
and therefore, y = 9 - x = 9 - 8 = 1
Therefore, the two digit number = 10x + y = 10*8 + 1 = 81
Therfore, the two-digit number = 10x + y and reversed number = 10y + x
Given:
x + y = 9 ----------1
Also given:
10x + y - 63 = 10y + x
9x - 9y = 63
x - y = 7 ------------2
Adding equation 1 and equation 2
2x = 16
x = 8
and therefore, y = 9 - x = 9 - 8 = 1
Therefore, the two digit number = 10x + y = 10*8 + 1 = 81
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