sum of the 3 consecutive arthemetic sequences is 15 and there product is 80, find the terms
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Answered by
0
Answer:
Call the numbers x-d, x, and x+d, d being the common difference between terms.
Then, x-d + x + x+d = 15 => 3x = 15, so x =5, and the other terms are 5-d and 5+d.
Now, (5-d)*5*(5+d) = 80 => (5-d)(5+d) = 25-d^2 = 16, so d^2 = 9 or d = + or - 3.
So, the three numbers are 2, 5, and 8. As a check, their sum and product are 15 and 80.
Step-by-step explanation:
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Answered by
1
Answer:
4,5,6
Step-by-step explanation:
let the sequence be x , x+1 , x+2
x+x+1+x+2 =15
3x + 3 = 15
3x = 12
x = 4
4 ,5, 6
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