Sum of the 5 terms of an arithmetic sequence is 45. What is the third term? The common difference is 4 write the first two terms? Write another arithmetic sequence having the sum of the first 5 terms is 45
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Answered by
20
Answer:
3rd term =9
first two terms=1,5
A,.P=1,5,9,13,17
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Answered by
3
Answer:
5term = 45 =5/2[2a+4(d)]
18 = 2a+4d
9 = a+2d
3rd term = a3 = a+2d= 9
d=4 a+2×4=9
{(a=1) a1=1,a2=5}
45= 5/2[2a+4d]
9=a+2d
suppose a3=3
9=3+2d
9-3=2d
6=2d
d=6/2=3
∴the arithmetic sequence of this sequence is 3,6,9,12,15
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