Sum of the 5th and 9th terms of an A.P 40 and the sum of 8th and 14th terms is 64 find the first term of 20th sums
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Step-by-step explanation:
a₅=a+4d
a₉=a+8d
a₈=a+7d
a₁₄=a+13d
a+4d+a+8d=40⇒2a+12d=40⇒a+6d=20⇒a=20-6d-(equation-1)
a+7d+a+13d=64⇒2a+20d=64⇒a+10d=32⇒a=32-10d-(equation-2)
equating both the equations for a
20-6d=32-10d⇒4d=12⇒d=3
a=20-6d=20-(6×3)=20-18=2
so a=2 and d=3
Sⁿ=n/2(2a+(n-1)d)
S₂₀=20/2(2×2 + 19×3)=10(4+57)=10×61=610
Sorry if there is any calculation mistake
the methods are all correct
hope this helps you
thank you
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