Question

sum of the age of father and son is 78. 6 years ago son's age was half of father. what is the present age of both?​

Answer 1

Step-by-step explanation:

let present age of son be = x

let present age of father be = (78-x)

son's age 6 years ago = (x-6)

father's age 6 years ago = (78-x-6)

= (72-x)

ATP,

72-x = x-6/2