Question

Sum of the ages of A and B is 52 years. If B's age is 2 years more than 1.5 times of the age of A ,find their individual ages.
a.20, 32
b. 18, 34
c. 30. 22
d. 16, 36​

Answer 1

(a) 20,32

Step-by-step explanation:

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Answer 2

$\LARGE\mathfrak{\pink{Solution:-}}$

$\large\mathbb{\orange{GIVEN:-}}$

• Sum of the ages of A and B is 52 years .
• Age of B is 2 years more than 1.5 times of the age of A .

$\large\mathbb{\purple{TO\: FIND:-}}$

Their individual age .

$\large\mathbb{\blue{ASSUMPTION:-}}$

Let, the age of A be x .

$\therefore$ the age of B is (1.5x + 2)

$\large\mathbb{\red{ACCORDING \:TO\: THE\: QUESTION:-}}$

$1x + ( 1.5x + 2 ) = 52 \\ \\ \implies \: 2.5x + 2 = 52\\ \\ \implies \: 2.5x = 52 - 2\\ \\ \implies \: 2.5x = 50\\ \\ \implies \: x = \frac{50}{2.5} \\ \\ \implies \: x = \frac{50 \times 10}{2.5 \times 10} \: (multiply \: both \: side \: with \: 10)\\ \\ \implies \: x = \frac{500}{25} \\ \\ \implies \: x = 20$

$\large\mathbb{\purple{ANSWER:-}}$

Age of A = x = 20 years .

Age of B = 1.5x + 2 = ( 20 × 1.5 ) + 2 = 30.0 + 2 = 32 years .

$\large\mathbb{\pink{FOCUS\: ZONE:-}}$

• Multiple 10 with both sides because to remove the decimal .