Sum of the ages of a father nd the son is 40 yrs if fathers age is three times tht of his son then find their respective ages
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2
Let , the age of son be x
Then , the age of father be 3x
Therefore ,
x + 3x = 40 [ °•° The sum of their ages is 40 ]
4x = 40
x = 40 / 4
x = 10
•°• The age of son is 10 years
And the age of father is ( 3 × 10 ) = 30 years
Then , the age of father be 3x
Therefore ,
x + 3x = 40 [ °•° The sum of their ages is 40 ]
4x = 40
x = 40 / 4
x = 10
•°• The age of son is 10 years
And the age of father is ( 3 × 10 ) = 30 years
Ashishkumar098:
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Answered by
1
let father age be x
and son age be y
x+y=40-------eq(1)
from second condition
y=3x
3x-y=0----------(2)
add eq(1)&(2)
we get,
4x=40
x=10
put x=10 in(1)
10+y=40
y=30
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