Question

Sum of the ages of a man and his son is 59. Three years hence the numerical product of their ages will be 750 .Find their present ages

Answer 1

Answer:

father's age = 47

son's age = 12

Step-by-step explanation:

let the age of father be x

age of son will be 59 - x

age of father after 3 yrs x + 3

age of son after 3 yrs 62 - x

product of ages after 3 yrs

$(x + 3)(62 - x) = 750\\ 62x - {x}^{2} + 186 - 3x = 750 \\ - { x }^{2} + 59x = 750 - 186 \\ {x}^{2} - 59x + 564 = 0 \\ {x}^{2} - 47x - 12x + 564 = 0 \\ x(x - 47) - 12(x - 47) = 0 \\ (x - 12)(x - 47) \\ x = 12 \: \: \: \: \: \: x = 47 \\ we \: take \: fathers \: age \: as \: 47 \\ as \: fathers \: age \: cannot \: be \: less \: than \: sons \: age$