Question

Sum of the ages of the father and the son is 40 years. Five years hence, father’s

age will be four times that of his son, find their respective ages.​

Answer 1

Answer:

= Present age of his son is  = 6YEARS

= Present age of his age is = 36 YEARS

Step-by-step explanation:

Let father's age be x and son's age be y

Thus,

x = 6y --------------(1)

Now after 4 years,

Father's age = x + 4

Son's age = y+4

Thus after 4 years,

x + 4 = 4(y + 4)

x + 4 = 4y + 16

From equation(1) -----> x = 6y

6y + 4 = 4y + 16

2y = 12

y = 6

Thus son's present age is 6 years

x = 6y

x = 6(6) = 36

Thus Father's present age is 36 years

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Answer 2

Answer:

The age of father and son are 35 and 5 respectively.

Step-by-step explanation:

Let the ages of father and the son be x and y respectively.

According to question,

x + y = 40

x = 40 - y          (1)

x + 5 = 4(y + 5)

x + 5 = 4y + 20

x - 4y = 20 - 5

x - 4y = 15

Put the value of x from equation (1),

40 - y - 4y = 15

40 - 5y = 15

-5y = 15 - 40

- 5y = - 25

5y = 25

y = 25/5

y = 5

Put the value of y in equation (1),

x = 40 - 5

x = 35

I hope this answer is helpful for you.