Question

Sum of the ages of three brothers born at intervals of 2 years is 60. What is the age of the youngest brother?

Answer 1

Answer:

Let the age of the youngest brother be 'x'.

It is given that, the difference of ages between each successive brother is 2 years.

So x is the age of younger brother, x + 2 is the age of second younger brother and x + 4 is the age of the eldest brother.

So adding up all we get 60 as the sum.

=> x + x + 2 + x + 4 = 60

=> 3x + 6 = 60

=> 3x = 60 - 6

=> 3x = 54

=> x = 54 / 3 = 18

Hence the age of the youngest brother is 18 years.