Sum of the ages of two brothers Amit and Sumit is 42 years. Before 6 years, Sumit's age was double the age of Amit. Find the present age of Sumit.
Answers
Answered by
1
before 6 years
let age of amit=x
let age of sumit=2x
ATQ
x + 2x = 42
3x = 42
x = 42÷3
x = 14
age of sumit = 2x
= 2×14
= 28 years
let age of amit=x
let age of sumit=2x
ATQ
x + 2x = 42
3x = 42
x = 42÷3
x = 14
age of sumit = 2x
= 2×14
= 28 years
Answered by
1
let the age of amit be x
let the age of sumit be 42-x
summit's age six yrs before =42-x-6
amit s age if yrs before =x-6
ATQ
42-x=2(x-6)
42-x=2x-12
-x-2x=-12-42
-3x=-54
x=18
age of amit=18
age of sumit =42-18=24
hope it was helpful
let the age of sumit be 42-x
summit's age six yrs before =42-x-6
amit s age if yrs before =x-6
ATQ
42-x=2(x-6)
42-x=2x-12
-x-2x=-12-42
-3x=-54
x=18
age of amit=18
age of sumit =42-18=24
hope it was helpful
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